Maths Differentiation and Applications of Derivatives JEE (Advanced) / IIT - JEE Problems ( Previous Years ) Numeric Response
Published on: August 14, 2026

A cylindrical container is to be made from certain solid material with the following constraints: It has fixed inner volume of V mm 3 , has a 2 mm thick solid wall and is open at the top. The bottom of the container is solid circular disc of thickness 2 mm and is of radius equal to the outer radius of the container.

If the volume of the material used to make the container is minimum when the inner radius of the container is 10 mm, then the value of is

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The correct answer is:
4

(4)

Volume of material V = π r 2 h

⇒ V 1 = π (r + 2) 2 2 + π (r + 2) 2 h – π r 2 h ⇒ V 1 = 2 π (r + 2) 2 + π h(4 + 4r)

⇒ V 1 = 2 π (r + 2) 2 + 4 π h(r + 1) ⇒ V 1 = 2 π

⇒ v = 10 3 π ⇒

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